\(y = x + 3\) is a linear equation and \(y = x^2 + 3x\) is a quadratic equation. If the product of two numbers is zero, then one or both numbers must also be equal to zero. To solve, put each bracket ...

Equations that have more than one unknown can have an infinite number of solutions. For example, \(2x + y = 10\) could be solved by: \(x = 1\) and \(y = 8\) \(x = 2\) and \(y = 6\) \(x = 3\) and \(y = ...

Okay, so I know that as soon as someone tells me what method to use, I'm gonna instantly remember it, but right now, I can think of only 1 way to solve simultaneous equations, and that doesn't work so ...